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This is the second of three exercises following the article 'Ruffing: sometimes it's good... but sometimes it isn't ***, which has been published earlier. To read that article, click Ruffing at bridge play. For exercise 1, click: Ruffing at bridge play- Exercise 1. | E/All | ♠ | 6 5 4 | | | | ♥ | A 8 5 4 | | ♦ | A J 7 6 4 3 | | ♣ | —
| | | |  | | | | | | | | | | ♠ | A J 7 | | | ♥ | 9 | | ♦ | K Q 10 9 8 5 | | ♣ | Q J 2 |
| West | North | East | South |
|---|
| — | —
| pass | 1♦ | | pass | 1♥ | pass
| 2♦ | | pass | 4♣1 | pass | 4♥2 | | pass | 5♦3 | pass | 6♦4 | | pass | pass | pass | |
1 Splinter: singleton or void in clubs; diamond fit; slam invitational 2 Control showing (a dangerous bid, since most pairs would consider this 4♥ bid to show a playable spot; meaning South tells North he may pass if his — North's — slam try was a minimal one; North would then be expecting something like ♥Kxx in South. This NS-pair, however, has agreed that 4♣ rules out hearts as trumps) 3 I've done enough 4 North has shown willingness to play 6♦ but has denied a spade control; since South has the ♠A and a very good hand (in view of his 2♦ bid) he surely must bid the slam
Perhaps North was a bit too eager, for this slam is too ambitious. West leads the ♣3. How should South play?
Solution Declarer is looking at two spade losers. At first sight he can pitch neither one of South's nor one of dummy's spades on a high card in the other hand. The chance that declarer, by playing spades himself, can avoid losing two spades, is not a good one. He has two chances, which he cannot combine: - East has both the ♠K and the ♠Q. In that case the winning line of play is to play a small spade to South's ♠J. Chance of success: 24%. - East or West has ♠Kx or ♠Qx or the bare ♠KQ, or West has a bare spade honour. In that case the winning line of play is to draw EW's single trump, cash the ♠A, eliminate the hearts and clubs (by cross-ruffing) ending in dummy and play the ♠7 from there (observe carefully what will happen next if the lay-out is as South hoped for). Chance of success: 16%.
On closer inspection there is a rather good chance after all that declarer can pitch one of dummy's spades losers on a winner in South. Which winner? A high club! Probably it's declarer's best chance: he has to hope West has underled the ♣K (or even the ♣A!): | W/All | ♠ | 6 5 4 | | | | ♥ | A 8 5 4 | | ♦ | A J 7 6 4 3 | | ♣ | — | | ♠ | K 8 3 2 |  | ♠ | Q 10 9 | | ♥ | K 7 6 2 | ♥ | Q J 10 3 | | ♦ | — | ♦ | 2 | | ♣ | K 9 6 4 3 | ♣ | A 10 8 7 5 | | | ♠ | A J 7 | | | ♥ | 9 | | ♦ | K Q 10 9 8 5 | | ♣ | Q J 2 |
So, onto the first trick he discards a spade from dummy. East wins with the ♣A and of course switches to a spade (not that it matters). South wins with the ♠A, draws trumps and plays the ♣Q. If West doesn't cover, declarer discards dummy's last spade. If West does cover the ♣Q, dummy ruffs and dummy's last spade disappears later on the ♣J. Twelve tricks.
PS: Against very good opponents this line of play is questionable. After all, a very good West who decides to lead a club, will elect the ♣K, since he knows dummy to have a singleton (or void) in clubs. That lead prevents the second round trump finesse against EW's remaining club honour, since East will still have his ♣A. So if West indeed is a very good player, by leading a small club he denies possession of a top club... |